Sum of Series (/* (1/(2!))+(2/(3!))(3/(4!))(4/(5!))+....+(n/(n+1!)))

/* (1/(2!))+(2/(3!))(3/(4!))(4/(5!))+....+(n/(n+1!))*/
#include
#include
#include
void main()
{
int i,n;
float sum=0;
int factorial(int);/*Prototype*/
clrscr();
printf("Enter Value 'n' to Find Series(1/(2!))+(2/(3!))+(3/(4!))+...+(n/(n+1!)) : ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+(i/factorial(i+1));
}
printf("\n\tSum is : %.2f",sum);
getch();
}
int factorial(int n)
{
int i,fact=1;
for(i=1;i<=n;i++)
fact=fact*i;
return(fact);
}
Output
Enter Value 'n' to Find Series(1/(2!))+(2/(3!))+(3/(4!))+...+(n/(n+1!)) : 3
Sum is :